Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.3 Computation in Positional Systems - Exercise Set 4.3: 30

Answer

$1580_{nine}$

Work Step by Step

$(6\times 3)_{10}=(18)_{10}=2\times 9+0=(20)_{9}$ Record the $0$; carry the $2$. $\begin{array}{llll} & 2 & 4 & 3_{nine}\\ \times & & & 6_{nine}\\ -- & -- & -- & --\\ & & & 0_{nine} \end{array}$ $(6\times 4+2)_{10}=(26)_{10}=2\times 9+8=(28)_{9}$ Record the $8$; carry the $2$. $\begin{array}{llll} & 2 & 4 & 3_{nine}\\ \times & & & 6_{nine}\\ -- & -- & -- & --\\ & & 8 & 0_{nine} \end{array}$ $(6\times 2+2)_{10}=(14)_{10}=1\times 9+5=(15)_{9}$ Record the $15.$ Result: $1580_{nine}$
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