Answer
To perform the given subtraction, write the numbers one over the other, such that the digits with same place value come in one line and then subtract column by column.
Also, if during subtraction, a borrow is required, then borrow 16 from the left column, because the subtraction involves base sixteen, and subtract 1 from the left column:
\[4\text{C}{{\text{6}}_{\text{sixteen}}}\]
\[\underline{-{{198}_{\text{sixteen}}}}\]
Now, solve the first column:
Since 6 is less than 8, borrow a 16 from the second column to the first column and subtract a 1 from the second column:
\[22-8={{\text{E}}_{\text{sixteen}}}\]
Now, solve the second column:
\[{{\text{B}}_{\text{sixteen}}}-{{9}_{\text{sixteen}}}={{2}_{\text{sixteen}}}\]
Now, solve the third column:
\[{{4}_{\text{sixteen}}}-{{1}_{\text{sixteen}}}={{3}_{\text{sixteen}}}\]
Hence, the overall subtraction can be summarized as follows:
\[4\text{C}{{\text{6}}_{\text{sixteen}}}\]
\[\underline{-{{198}_{\text{sixteen}}}}\]
\[32{{\text{E}}_{\text{sixteen}}}\]
To check whether the above-obtained solution is correct, perform the subtraction in base ten:
\[4\text{C}{{\text{6}}_{\text{sixteen}}}\][{{198}_{\text{sixteen}}}=408\]and \[32{{\text{E}}_{\text{sixteen}}}=814\].
Since indeed equals 814, the solution obtained is correct.
