Answer
$15120$
Work Step by Step
If we want to choose $k$ elements out of $n$ regarding the order, not allowing repetition, we can do this in $_{n}P_k=\frac{n!}{(n-k)!}$ ways.
Hence here because we have $9$ acts for $5$ spots, $_{9}P_5=\frac{9!}{(9-5)!}=9\cdot8\cdot7\cdot6\cdot5=15120$
