Chapter 11 - Counting Methods and Probability Theory - 11.3 Combinations - Exercise Set 11.3 - Page 708: 50

4495 bowls

The order of the chosen flavors does not matter. Combinations, ${}_{n}C_{r}=\displaystyle \frac{n!}{(n-r)!r!}$ ${}_{31}C_{3}=\displaystyle \frac{31!}{(31-3)!3!}=\frac{31\times 30\times 29}{1\times 2\times 3}$ $=\displaystyle \frac{31\times 5\times 29}{1\times 1\times 1}= 4495$