## Basic College Mathematics (9th Edition)

$k=4$
We are given the equation $3(k-6)=6-12$. In order to solve, we must first use the distributive property to simplify the left side. $3(k-6)=3(k)+3(-6)=3k-18=6-12$ Combine like terms on the right side. $3k-18=6-12=-6$ Add 18 to both sides. $3k-18+18=-6+18$ $3k=12$ Divide both sides by 3. $\frac{3k}{3}=\frac{12}{3}$ Therefore, $k=4$.