Answer
The length of the park is $550$ yd and the width is $110$ yd.
Work Step by Step
1. Solve for $x$ in the equation below
Width = $x$
Length = $5x$
$2(5x) + 2(x) = 1320$ (There are two widths and two lengths)
$10x + 2x = 1320$
$12x = 1320$
$x = 110$
2. Substitute the value into the lengths and widths
Width $ = x$
Width $ = 110$ yd
Length $= 5x$
Length $ = 5(110$
Length $= 550$ yd
Therefore the length of the park is $550$ yd and the width is $110$ yd.