## Basic College Mathematics (9th Edition)

The length of the park is $550$ yd and the width is $110$ yd.
1. Solve for $x$ in the equation below Width = $x$ Length = $5x$ $2(5x) + 2(x) = 1320$ (There are two widths and two lengths) $10x + 2x = 1320$ $12x = 1320$ $x = 110$ 2. Substitute the value into the lengths and widths Width $= x$ Width $= 110$ yd Length $= 5x$ Length $= 5(110$ Length $= 550$ yd Therefore the length of the park is $550$ yd and the width is $110$ yd.