## Basic College Mathematics (9th Edition)

Published by Pearson

# Chapter 9 - Basic Algebra - Review Exercises: 136

#### Answer

The length of the park is $550$ yd and the width is $110$ yd.

#### Work Step by Step

1. Solve for $x$ in the equation below Width = $x$ Length = $5x$ $2(5x) + 2(x) = 1320$ (There are two widths and two lengths) $10x + 2x = 1320$ $12x = 1320$ $x = 110$ 2. Substitute the value into the lengths and widths Width $= x$ Width $= 110$ yd Length $= 5x$ Length $= 5(110$ Length $= 550$ yd Therefore the length of the park is $550$ yd and the width is $110$ yd.

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