## Basic College Mathematics (9th Edition)

$y = 20$
$\frac{y}{2} - 2 = \frac{y}{4} + 3$ $y - (2 \times 2) = \frac{y \times 2}{4} + (3 \times 2)$ $y - 4 = \frac{2y}{4} + 6$ $(y \times 4) - (4 \times 4) = 2y + (6 \times 4)$ $4y - 16 = 2y + 24$ $2y - 16 = 24$ $2y = 40$ $y = \frac{40}{2}$ $y = 20$