Chapter 9 - Basic Algebra - 9.7 Solving Equations with Several Steps - 9.7 Exercises - Page 681: 74

$z = 24$

$\frac{z}{3} + 1 = \frac{z}{2} -3$ $z + (1 \times 3) = \frac{z \times 3}{2} - (3 \times 3)$ $z + 3 = \frac{3z}{2} - 9$ $(z \times 2) + (3 \times 2) = 3z - (9 \times 2)$ $2z + 6 = 3z - 18$ $-z + 6 = -18$ $-z = -24$ $z = 24$