Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises: 27

Answer

Hypotenuse $\approx 11.7$ yd.

Work Step by Step

Let $H =$ hypotenuse of the triangle $a^{2} + b^{2} = c^{2}$ $4^{2} + 11^{2} = H^{2}$ $16 + 121 = H^{2}$ $137 = H^{2}$ $H = \sqrt 137$ $H = 11.704...$ $H \approx 11.7$ yd
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