Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 594: 28

Answer

Hypotenuse $\approx 12.2$ km.

Work Step by Step

Let $H =$ hypotenuse of the triangle $a^{2} + b^{2} = c^{2}$ $7^{2} + 10^{2} = H^{2}$ $49 + 100 = H^{2}$ $149 = H^{2}$ $H = \sqrt 149$ $H = 12.206...$ $H \approx 12.2$ km
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.