Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - Summary Exercises - Operations with Fractions - Page 235: 13

Answer

$\frac{7}{6}$

Work Step by Step

$\frac{35}{45}\div\frac{10}{15}=\frac{35}{45}\times\frac{15}{10}=\frac{35\div5}{45\div5}\times\frac{15\div5}{10\div5}=\frac{7}{9}\times\frac{3}{2}$ $\frac{7}{9}\times\frac{3}{2}=\frac{7\times3}{9\times2}=\frac{21}{18}=\frac{21\div3}{18\div3}=\frac{7}{6}$
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