Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - Summary Exercises - Operations with Fractions: 18

Answer

$\frac{1}{12}$

Work Step by Step

$\frac{5}{6}-\frac{3}{4}=\frac{5\times2}{6\times2}-\frac{3\times3}{4\times3}=\frac{10}{12}-\frac{9}{12}=\frac{10-9}{12}=\frac{1}{12}$
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