Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 15 - Multiple Integrals - 15.9 Exercises - Page 1061: 5

Answer

Half-Cone

Work Step by Step

Conversion of rectangular to spherical coordinates is as follows: $x=\rho \sin \phi \cos \theta; y=\rho \sin \phi \sin \theta;z=\rho \cos \phi$ and $\rho=\sqrt {x^2+y^2+z^2}$; $\cos \phi =\dfrac{z}{\rho}$; $\cos \theta=\dfrac{x}{\rho \sin \phi}$ Here, $\theta=\dfrac{\pi}{3}$ $\cos \phi =\cos \dfrac{\pi}{3} =\dfrac{1}{2}$; $\cos \theta=\dfrac{0}{2 \sin \dfrac{\pi}{6}} \implies \theta=0$ This implies that $\rho^2 \cos^2 \phi =\dfrac{1}{4}\rho^2$ or, $z^2=\dfrac{1}{4}(x^2+y^2+z^2$ Thus, we have $3z^2=x^2+y^2$ This equation represents the half cone.
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