Answer
Yes
Work Step by Step
Let $v_1$ be vector in the line containing the first two points.
$v_1=\lt-2-(-4),0-(-6),-3-1\gt$
$=\lt 2,6,-4\gt$
$=2\lt\lt 1,3,-2\gt$
Let $v_2$ be vector in the line containing the second two points.
$v_2=\lt10-5,18-3,4-14\gt$
$=\lt 5,15,-10\gt$
$=5\lt 1,3,-2\gt$
Then $v_1 \parallel v_2 $ because they are scalar multiples of each other.
