Answer
$r=(2+3t)i+(2.4+2t)j+(3.5-t)k$
and
$x=2+3t,y=2.4+2t,z=3.5-t $
Work Step by Step
Equation of the line is given by $r=r_0+tv$
$r=\lt 2,2.4,3.5\gt $
Thus, the vector equation of the line is
$r=(2i+2.4j+3.5k)+t(3i+2j-k)$
$r=(2+3t)i+(2.4+2t)j+(3.5-t)k$
Hence, the parametric equations are:
$x=2+3t,y=2.4+2t,z=3.5-t $