Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.5 Exercises - Page 848: 3

Answer

$r=(2+3t)i+(2.4+2t)j+(3.5-t)k$ and $x=2+3t,y=2.4+2t,z=3.5-t $

Work Step by Step

Equation of the line is given by $r=r_0+tv$ $r=\lt 2,2.4,3.5\gt $ Thus, the vector equation of the line is $r=(2i+2.4j+3.5k)+t(3i+2j-k)$ $r=(2+3t)i+(2.4+2t)j+(3.5-t)k$ Hence, the parametric equations are: $x=2+3t,y=2.4+2t,z=3.5-t $
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