Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.4 Exercises - Page 839: 44

Answer

(a) $v =\lt x, 2x-5,x-1 \gt$ (b) No possible solutions

Work Step by Step

(a) Let $v= \lt x,y,z \gt$ then $\lt 1,2,1 \gt \times v=\lt 1,2,1 \gt \times \lt x,y,z \gt= \lt 2z-y, x-z, y-2x \gt$ and $ \lt 2z-y, x-z, y-2x \gt = \lt 3,1,-5 \gt$ which gives us a system of equations. $2z-y=3$ $x-z=1$ $y-2x =-5$ Simplify it. $z=x-1$, $2x-y=5$ or $y=2x-5$ Hence, $v =\lt x, 2x-5,x-1 \gt$ (b) Let $v= \lt x,y,z \gt$ then $\lt 1,2,1 \gt \times v=\lt 1,2,1 \gt \times \lt x,y,z \gt= \lt 2z-y, x-z, y-2x \gt$ and $ \lt 2z-y, x-z, y-2x \gt = \lt 3,1,-5 \gt$ which gives us a system of equations. $2z-y=3$ ... (1) $x-z=1$ ... (2) $y-2x =-5$ ...(3) Simplify it. $z=x-1$ .... (4) , $2x-y=5$ or $y=2x-5$ .... (5) If we add equations (3) and (5), we get $0=10$ which means the system is inconsistent and there are no solutions.
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