Answer
16 units
Work Step by Step
Area of a parallelogram with vertices $ABCD$ is defined as:
$|{AB} ^{ \to} \times {AD}^{ \to}|$
Here,
${AB} ^{ \to} =\lt 0--2,4-1 \gt= \lt 2,3 \gt$
${AD} ^{ \to} =\lt 2--2,-1-1 \gt= \lt 4,-2 \gt$
$|{AB} ^{ \to} \times {AD}^{ \to}|=|\lt 4,-2 \gt \times \lt 2,3 \gt| $
$=|-16|$
$=16$ units