Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.2 Exercises - Page 823: 23

Answer

$\frac{-3}{\sqrt{58}}i+\frac{7}{\sqrt{58}}j$

Work Step by Step

Let $\mathbf v=-3i+7j$. We can obtain a unit vector in the same direction as $\mathbf v$ by multiplying $\mathbf v$ by $\frac{1}{|\mathbf v|}$. By definition, $|\mathbf v|=\sqrt{(-3)^2+7^2}=\sqrt{9+49}=\sqrt{58}$. So $\frac{\mathbf v}{|\mathbf v|}=\frac{\mathbf v}{\sqrt{58}}=\frac{-3i+7j}{\sqrt{58}}=\frac{-3}{\sqrt{58}}i+\frac{7}{\sqrt{58}}j$ is a unit vector in the same direction as $\mathbf v$.
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