Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.2 Exercises - Page 823: 11

Answer

$\lt 3,-1 \gt$

Work Step by Step

Find vector for $ \vec {AB}$ $ \vec {AB}=\lt x_2-x_1,y_2-y_1 \gt$ $ \vec {AB}=\lt 2-(-1),2-3 \gt$ $ \vec {AB}=\lt 3,-1 \gt$ The equivalent representation, starting at the origin, is a vector from point $(0,0)$ to the point $\lt 3,-1 \gt$.
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