Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Exercises - Page 700: 9

Answer

Equation of parabola is $y^{2}=-x$ Focus: $(-\frac{1}{4},0)$ Directrix : $x=\frac{1}{4}$

Work Step by Step

$y^{2}=4px$ is the equation of the parabola with vertex $(0,0)$ focus $(p,0)$ and directrix $x=-p$ From the graph, we can see that $(-1,1)$ is a point on the curve. Thus, $(1)^{2}=4p(-1)$ Hence, $p=-\frac{1}{4}$ Equation of parabola is: $y^{2}=-x$ Focus: $(-\frac{1}{4},0)$ Directrix : $x=\frac{1}{4}$
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