Answer
Hyperbola
Foci: $( \pm \sqrt 2,0)$
Vertices: $(\pm1,0,)$
Work Step by Step
$\frac{x^{2}}{1}-\frac{y^{2}}{1}=1$, the equation of a hyperbola.
$c^{2}=1^2+1^2$
$c=\sqrt 2$
Foci: $( \pm \sqrt 2,0)$
Vertices: $(\pm1,0,)$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Exercises - Page 700: 26
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