Answer
See image:
Work Step by Step
$ \begin{array}{llll}
\text{Function:} & f(x)=-x^{2}+4x-4 & a =-1, b=4, c=-4 & \\
\text{coefficient a} & \text{negative, opens down} & \\ & \\
\text{Vertex} & x_{V}=-b/(2a) & y_{V}=f(-b/(2a) & \\
& x_{V}=2 & y_{V}=0 & \\
& \bf V(2,0) & & \\\\
\text{Line of symmetry} & x=2 & & \\
\text{y intercept} & c=-4, & \bf(0,-4) & \\
\text{point symmetric to } & & & \\
\text{the y-intercept} & x=2x_{V}=4 & \bf(4,-4)\\ & \\
\text{Zeros:} & -x^{2}+4x-4=0 & & \\
& -(x^{2}-4x+4)=0 & & \\
& -(x-2)^{2}=0 & & \\
& x=2 & & \\
& \bf(2,0) & &
\end{array}$
Additional points: (1,-1), (3,-1).
Using the above information, plot the points and join with a smooth curve (parabola).