Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Secton 9.1 - Quadratic Functions and Models - Exercises - Page 627: 2

Answer

vertex = (-1/2,1/4) y intercept (0,0) x intercepts -1,0

Work Step by Step

f(x) = -x^{2}-x+0 x vertex=\frac{-b}{2a}=-\frac{1}{2} y=-(-1/2)^2-(-1/2)+0=1/4 so vertex=(-1/2 , 1/4) y intercept y=c=0 x intercepts 0=-x^2-x=0 = (-x-1)(x+0) x=-1,0
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