Answer
$0.34$
Work Step by Step
Let us consider that $A$ denotes a randomly chosen polled person who agrees with the first proposition and $B$ denotes a randomly chosen polled person who agrees with the second proposition .
Thus, we can find the probability of a person who agrees with the both statements and assumes $A$ and $B$ as independent events.
$P( A \cap B)=P(A)P(B)=(0.79)(0.43)=0.34$