Chapter 7 - Section 7.5 - Conditional Probability and Independence - Exercises - Page 508: 50

$0.21 $

Let us consider that $A$ denotes a randomly chosen polled person who agrees with the first proposition and $B$ denotes a randomly chosen polled person who agrees with the second proposition . Thus, we can find the probability of a person who agrees with the both statements and assumes $A$ and $B$ as independent events. $P( A \cap B)=P(A)P(B)=(0.49)(0.43) =0.21 $