Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.2 - Relative Frequency - Exercises - Page 466: 33

Answer

See the picture.

Work Step by Step

$N=2000$ Frequency of "Dialup": $fr(Dialup)=P(Dialup)\times N=0.628\times2000=1256$ Frequency of "Cable Moden": $fr(Cable~Moden)=P(Cable~Moden)\times N=0.206\times2000=412$ Frequency of "DSL": $fr(DSL)=P(DSL)\times N=0.151\times2000=302$ Frequency of "Other": $fr(Other)=P(Other)\times N=0.015\times2000=30$
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