Answer
See the picture.
Work Step by Step
$N=1+4+4+1=10$
Relative frequency of "3":
$P(3)=\frac{fr(3)}{N}=\frac{1}{10}=0.10$
Relative frequency of "2":
$P(2)=\frac{fr(2)}{N}=\frac{4}{10}=0.40$
Relative frequency of "1":
$P(1)=\frac{fr(1)}{N}=\frac{4}{10}=0.40$
Relative frequency of "0":
$P(0)=\frac{fr(0)}{N}=\frac{1}{10}=0.10$
