Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.2 - Relative Frequency - Exercises - Page 464: 6

Answer

$0.333$

Work Step by Step

$N=90$ because the die is rolled 60 times. $E$ is the event that the number that comes up is at least 4. (4,5,or 6): 4 come up 30 times, 5 and 6 come up 15 times each. $fr(E)=30+15+15=60$ $P(E)=\frac{fr(E)}{N}=\frac{60}{90}=\frac{1}{3}\approx 0.333$
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