Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.2 - Relative Frequency - Exercises - Page 464: 5

Answer

$0.6$

Work Step by Step

$N=60$ because the die is rolled 60 times. $E$ is the event that the number that comes up is at most 4. (1,2,3 or 4.) 1,2, and 3 each come up 8 times, 4 comes up 12 times. $fr(E)=8+8+8+12=36$ $P(E)=\frac{fr(E)}{N}=\frac{36}{60}=0.6$
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