Answer
$161,700$
Work Step by Step
The number of combinations of 100 items taken 97 at a time :
$C(100,97)=\frac{100!}{97!(100-97)!}=\frac{100!}{97!*3!}=\frac{100*99*98*97*...*3*2*1}{97*96*,,,*2*1*3*2*1}=\frac{100*99*98}{6}=161,700$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 6 - Section 6.4 - Permutations and Combinations - Exercises - Page 437: 16
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