Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 6 - Section 6.4 - Permutations and Combinations - Exercises - Page 437: 26

Answer

$10$

Work Step by Step

The number of three-letter (unordered) sets that use letters b,o,g,e,y at most once each equals to the number of combinations of 5 items taken 3 at a time : $C(5,3)=\frac{5!}{3!(5-3)!}=\frac{5!}{3!*2!}=\frac{5*4*3*2*1}{3*2*1*2*1}=5*2=10$
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