Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 6 - Section 6.2 - Cardinality - Exercises - Page 417: 67

Answer

if $B\subseteq A$

Work Step by Step

CardinaIity of a Union: If A and $B$ are finite sets, then $n(A\cup B)=n(A)+n(B)-n(A\cap B)$. So the equality $n(A\cup B)=n(A)$ stands if $n(B)-n(A\cap B)$=0, that is, $n(B)$=$n(A\cap B)$. This can only be if B is contained in A, or equal to A.
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