Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 6 - Section 6.2 - Cardinality - Exercises: 50

Answer

n($ P^{\prime}\cup$N )=90 (number of stocks that are either pharmaceutical, or have changed in value, or both)

Work Step by Step

P$\cup N^{\prime}$ is the set of stocks that are either pharmaceutical, or have changed in value, or both Cardinality of union: n(P$\cup N^{\prime}$ )= n(P) +n($N^{\prime}$) -n(P$\cap$N') n(P)= 50 n(N')=n(S)-n(N)=100- 40 n (P$\cap N^{\prime}$)= 10+10 (in column P, all that are not N) n($ P^{\prime}\cup$N )=50+60-20=90
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