Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 11 - Section 11.1 - Derivatives of Powers, Sums, and Constant Multiples - Exercises - Page 795: 21

Answer

$g^{\prime}(x)=-2x^{-3}+3x^{-2}$

Work Step by Step

SUMMARY: The Power Rule$:\ \ \ [x^{n}]^{\prime}=nx^{n-1 } $ Sum Rule: $\ \ \ \ \ \ [f\pm g]^{\prime}(x)=f^{\prime}(x)\pm g^{\prime}(x) $ Constant Multiple Rule:$\ \ \ [cf]^{\prime}(x)=cf^{\prime}(x) $ Constant times x:$\ \ \ \displaystyle \frac{d}{dx}(cx)=c $ Constant:$\displaystyle \ \ \ \ \ \frac{d}{dx}(c)=0 $ -------------------------------- $g^{\prime}(x)=[x^{-2}-3x^{-1}-2]^{\prime}=... $Sum Rule, $=[x^{-2}]^{\prime}-[3x^{-1}]^{\prime}-[2]^{\prime}=$... individually: $[x^{-2}]^{\prime}$=...power rule...$=-2x^{-3}$ $[3x^{-1}]^{\prime}=$...Constant Multiple Rule... $=3[x^{-1}]^{\prime}=$...power rule...$=3(-1\cdot x^{-2})=-3x^{-2}$ $[2]^{\prime}=...$Constant$...=0$ So $g^{\prime}(x)=-2x^{-3}-(-3x^{-2})-0$ $g^{\prime}(x)=-2x^{-3}+3x^{-2}$
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