Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 1 - Section 1.2 - Functions and Models - Exercises - Page 71: 11

Answer

$\frac{x^2}{2}$

Work Step by Step

The length of the field is $x$. The length equals to twice its width. Therefore, its width is $\frac{x}{2}$. The area of the field will be (length*width=) $x*\frac{x}{2}=\frac{x^2}{2}$
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