Answer
$s(x)=x^2+x$ with domain all real numbers, $s(-3)=6$
Work Step by Step
$f(x)=x^2+1$
$g(x)=x-1$
$s(x)=f(x)+g(x)=x^2+1+x-1=x^2+x$
The domain of $f(x)$ and $g(x)$ is all real numbers, so that will be the domain of $s(x)$ too.
$s(-3)=(-3)^2-3=9-3=6$
