Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 7 - Problems Plus - Problems - Page 541: 3

Answer

The given integral is: $$ \int_{0}^{1}(\sqrt[3]{1-x^{7}}-\sqrt[7]{1-x^{3}}) d x=0 $$

Work Step by Step

Evaluate $$ \int_{0}^{1} (\sqrt[3] {1-x^{7 }} - \sqrt[7] {1-x^{3 }} )d x $$ The given integral represents the difference of the shaded areas, which appears to be 0. It can be calculated by integrating with respect to either $x$ or $y$ so we find $x$ in terms of $y$ for each curve: $$ y=\sqrt[3]{1-x^{7}} \Rightarrow x=\sqrt[7]{1-y^{3}} $$ $$ y=\sqrt[7]{1-x^{3}} \Rightarrow x=\sqrt[3]{1-y^{7}}, $$ so $$ \int_{0}^{1}(\sqrt[3]{1-y^{7}}-\sqrt[7]{1-y^{3}}) d y=\int_{0}^{1}(\sqrt[7]{1-x^{3}}-\sqrt[3]{1-x^{7}}) d x $$ But this equation is of the form $ z=-z. $ So $$ \int_{0}^{1}(\sqrt[3]{1-x^{7}}-\sqrt[7]{1-x^{3}}) d x=0 $$
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