Answer
=$3.75$
Work Step by Step
$\int_{-1}^{2}$ $x^{3} dx$
=$\frac{x^4}{4}$| $_{-1}^{2}$
=[$\frac{2^4}{4}$] - [$\frac{-1^4}{4}$]
=[$\frac{16}{4}$] - [$\frac{1}{4}$]
=$\frac{15}{4}$
=$3.75$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 5 - Section 5.3 - The Fundamental Theorem of Calculus - 5.3 Exercises - Page 400: 53
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