Answer
$\int_{0}^{\pi} sin~x~dx = 2$
Work Step by Step
We can find the area under the graph:
$\int_{0}^{\pi} sin~x~dx$
$=-cos~x~\vert_{0}^{\pi}$
$=-cos(\pi)-[-cos(0)]$
$=-(-1)-(-1)$
$=1+1$
$=2$
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