Answer
Does not exist since the function has an infinite discontinuity at $t = 4$. $f$ is discontinuous on the interval $[ 1,5]$.
Work Step by Step
$\int^{5}_1 \frac{dt}{(t-4)^{2}}$
$t -4 \ne 0$
$t \ne 4$
Does not exist since the function has an infinite discontinuity at $t = 4$. $f$ is discontinuous on the interval $[ 1,5]$.
