Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.9 - Related Rates - 3.9 Exercises - Page 249: 18

Answer

The length of the shadow is decreasing at a rate of $0.6~m/s$

Work Step by Step

Let $x$ be the man's distance from the spotlight. Let $z$ be the height of the shadow. We can use similar triangles to write an expression for $z$: $\frac{z}{12} = \frac{2}{x}$ $z = \frac{24}{x}$ We can differentiate both sides of the equation with respect to $t$: $z = \frac{24}{x}$ $\frac{dz}{dt} = \frac{-24}{x^2}~\frac{dx}{dt}$ $\frac{dz}{dt} = [\frac{-24}{(8)^2}~]~(1.6)$ $\frac{dz}{dt} = -0.6$ The length of the shadow is decreasing at a rate of $0.6~m/s$.
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