Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.9 - Related Rates - 3.9 Exercises - Page 249: 4

Answer

$140 \frac{cm^{2}}{s}$

Work Step by Step

Use the area of the rectangle: $(A = lw)$ $\frac{dA}{dt} = \frac{dl}{dt}w + l\frac{dw}{dt}$ $\frac{dA}{dt} = 8(10) + 20(3)$ $\frac{dA}{dt} = 80 + 60$ $\frac{dA}{dt} = 140 \frac{cm^{2}}{s}$
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