Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.4 - The Chain Rule - 3.4 Exercises - Page 204: 24

Answer

$f'(t)=3(\ln2)t^{2}(2^{t^{3}})$

Work Step by Step

$f(t)=2^{t^{3}}$ Differentiate using the chain rule: $f'(t)=(2^{t^{3}})(\ln2)(t^{3})'=(2^{t^{3}})(\ln2)(3t^{2})=3(\ln2)t^{2}(2^{t^{3}})$
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