Answer
$f'(x)=-2\theta\sin(\theta^{2})$
Work Step by Step
$f(\theta)=\cos(\theta^{2})$
Differentiate using the chain rule:
$f'(\theta)=-\sin(\theta^{2})(\theta^{2})'=-\sin(\theta^{2})(2\theta)=-2\theta\sin(\theta^{2})$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Section 3.4 - The Chain Rule - 3.4 Exercises - Page 204: 11
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