Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.4 - The Chain Rule - 3.4 Exercises: 11

Answer

$f'(x)=-2\theta\sin(\theta^{2})$

Work Step by Step

$f(\theta)=\cos(\theta^{2})$ Differentiate using the chain rule: $f'(\theta)=-\sin(\theta^{2})(\theta^{2})'=-\sin(\theta^{2})(2\theta)=-2\theta\sin(\theta^{2})$
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