Answer
$y'=\cos^{2}\theta-\sin^{2}\theta$
Work Step by Step
$y=\sin\theta\cos\theta$
Differentiate using the product rule:
$y'=(\sin\theta)(\cos\theta)'+(\cos\theta)(\sin\theta)'=...$
$...=(\sin\theta)(-\sin\theta)+(\cos\theta)(cos\theta)=-\sin^{2}\theta+\cos^{2}\theta=\cos^{2}\theta-\sin^{2}\theta$