Answer
$y'=y'=2\sec x\tan x+\csc x\cot x$
Work Step by Step
$y=2\sec x-\csc x$
Differentiate each term
$y'=(2\sec x)'-(\csc x)'=2\sec x\tan x+\csc x\cot x$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Section 3.3 - Derivatives of Trigonometric Functions - 3.3 Exercises - Page 196: 4
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