## Calculus: Early Transcendentals 8th Edition

$\frac{7}{2}x-3$
First, look at each term separately using sum/difference rule. $\frac{d}{dx}(\frac{7}{4}x^2)-\frac{d}{dx}(3x)+\frac{d}{dx}(12)$ Then take derivative using general power rule. $\frac{7}{4}*2x-3*1+0$