Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.1 - Derivatives of Polynomials and Exponential Functions - 3.1 Exercises: 32

Answer

$$y'=e^{x+1}$$

Work Step by Step

$$y=e^{x+1}+1$$ $$y=e^x\times e+1$$ So, the derivative of $y$ is $$y'=e\frac{d}{dx}(e^x)+\frac{d}{dx}(1)$$ (since $e$ is a number) $$y'=e\times(e^x)+0$$ $$y'=e^{x+1}$$
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