Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Review - Concept Check - Page 266: 1

Answer

a) Power Rule: $\frac{d}{dx}x^{n} = nx^{n-1}$ b) The Constant Multiple Rule: $\frac{d}{dx}(c \times f(x)) = c\frac{d}{dx}(f(x)) $ c) Sum Rule: $\frac{d}{dx}(f(x) + g(x)) = \frac{d}{dx}(f(x)) + \frac{d}{dx}(g(x))$ d) Difference Rule: $\frac{d}{dx}(f(x) - g(x)) = \frac{d}{dx}(f(x)) - \frac{d}{dx}(g(x))$ e) Product Rule: $\frac{d}{dx}(f(x) \times g(x)) = \frac{d}{dx}(f(x))\times g(x) + \frac{d}{dx}(g(x))\times f(x)$ f) Quotient Rule: $\frac{d}{dx}(\frac {f(x)}{g(x)}) = \frac{\frac{d}{dx}(f(x))\times g(x) - \frac{d}{dx}(g(x))\times f(x)}{(g(x))^{2}}$ g) Chain Rule: $\frac{d}{dx}(f(g(x))) = f'(g(x))\times g'(x)$

Work Step by Step

a) Power Rule: $\frac{d}{dx}x^{n} = nx^{n-1}$ b) The Constant Multiple Rule: $\frac{d}{dx}(c \times f(x)) = c\frac{d}{dx}(f(x)) $ c) Sum Rule: $\frac{d}{dx}(f(x) + g(x)) = \frac{d}{dx}(f(x)) + \frac{d}{dx}(g(x))$ d) Difference Rule: $\frac{d}{dx}(f(x) - g(x)) = \frac{d}{dx}(f(x)) - \frac{d}{dx}(g(x))$ e) Product Rule: $\frac{d}{dx}(f(x) \times g(x)) = \frac{d}{dx}(f(x))\times g(x) + \frac{d}{dx}(g(x))\times f(x)$ f) Quotient Rule: $\frac{d}{dx}(\frac {f(x)}{g(x)}) = \frac{\frac{d}{dx}(f(x))\times g(x) - \frac{d}{dx}(g(x))\times f(x)}{(g(x))^{2}}$ g) Chain Rule: $\frac{d}{dx}(f(g(x))) = f'(g(x))\times g'(x)$
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