Answer
$$\lim\limits_{x\to1}e^{x^3-x}=1$$
Work Step by Step
$$A=\lim\limits_{x\to1}e^{x^3-x}$$
Since $e^{x^3-x}$ is an exponential function, it is continuous at any number in its domain, which is $R$. That means
$A=\lim\limits_{x\to1}e^{x^3-x}=e^{1^3-1}=e^0=1$
