Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Review - Exercises: 3

Answer

$$\lim\limits_{x\to1}e^{x^3-x}=1$$

Work Step by Step

$$A=\lim\limits_{x\to1}e^{x^3-x}$$ Since $e^{x^3-x}$ is an exponential function, it is continuous at any number in its domain, which is $R$. That means $A=\lim\limits_{x\to1}e^{x^3-x}=e^{1^3-1}=e^0=1$
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